Question

Shiela is competes in the long jump event. If she jumps at an angle 22.7° above horizontal, and with an initial velocity of 9.44 m/s, what will her range be?

Select one:



a.6.46 m



b. 5.10 m



c. 7.22 m



d.8.04 m

Answer 1

To find the range of Shiela's long jump, we use the equation for range: Range = (initial velocity squared * sin(2 * angle)) / g. Plugging in the given values, we find that the range will be 5.10 m.

Step-by-step explanation:

To find the range, we need to consider the horizontal motion of the long jumper. Assuming no air resistance, the range is given by the equation:

Range = (initial velocity squared * sin(2 * angle)) / g

Plugging in the given values:

1. Initial velocity: 9.44 m/s
2. Angle: 22.7°
3. Acceleration due to gravity: 9.8 m/s^2

Range = (9.44 squared * sin(2 * 22.7°)) / 9.8 = 5.10 m

Therefore, the range of Shiela's jump will be 5.10 m

Answer 2

To calculate the range of Shiela's long jump, we use the projectile motion formula, considering the given initial velocity and takeoff angle. After performing the calculation, Shiela's range is determined to be approximately 6.46 meters. So the correct option is a.

Step-by-step explanation:

The question asks to find the range of a long jump, given an initial velocity and an angle of takeoff. This can be solved using the formula for the range of a projectile:

R = (v^2 ∗ sin(2 θ)) / g

where R is the range, v is the initial velocity, θ is the angle of takeoff, and g is the acceleration due to gravity (9.81 m/s^2 on Earth). Since the angle given is above the horizontal, we first need to find the equivalent angle θ for the formula by doubling it since sin(2θ) is used. This leads to:

R = (9.44 m/s)^2 ∗ sin(2×22.7°) / 9.81 m/s^2

Calculating the sine of double the angle and then plugging the numbers into the formula gives us Shiela's range. After calculations, we find the answer is close to option a, which is 6.46 m.