Question

How to solve:
10-2+(-3-4)-1-(-5)=

Answer 1

5

Explanation:

-(-5)

= - x (- 5)

= 5

(- 3 - 4)

= (- 3) + (- 4)

= - 7

10 - 2 + (- 3 - 4) - 1 - (- 5)

= 8 + (- 7) - 1 + 5

= 8 + 5 + (- 7) + (- 1)

= 8 + 5 + (- 8)

= 8 - 8 + 5

= 0 + 5

= 5

Answer 2

Detailed below

Explanation:

The best way to remember how to solve, even if you haven't reached this stage yet, is the acronym BEDMAS (Brackets, Exponents, Division, Multiplication, Addition, Subtraction) in which the operations are performed in order of left to right. Since you have an equation in brackets, solve that first. (-3-4 = -7) And rewrite the equation 10-2+(-7)-1-(-5) = ?

Now rewrite again to simplify the negative integers. 10-2-7-1+5 = 5