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150 mL of oxygen is collected over water at 19.0°C and 750 torr. If the dry volume becomes 100 mL and the pressure becomes 1.00 atm, what will be the new temperature?

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Answer: 0.252K

Explanation: V1=150ml V2=100ml

P1=750atm P2=1atm

T1=292K T2=?

(P1V1)/T1 = (P2V2)/T2

T2=0.252K

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User S McCrohan
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