Question

find the acceleration of the car from rest with an inintial velocity of 0.02 m/s unfomly travel of 5.06 second with a distance of 25.m? ​

Answer 1

\(a = \frac{2(25 - 0.02 \cdot 5.06)}{5.06^2}\)

Simplifying further:

\(a = \frac{2(25 - 0.1012)}{25.6036}\)

\(a = \frac{2(24.8988)}{25.6036}\)

\(a = \frac{49.7976}{25.6036}\)

\(a \approx 1.945 \, \text{m/s}^2\)

Therefore, the acceleration of the car, given the provided information, is approximately \(1.945 \, \text{m/s}^2\).