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4 resistors of resistance 2 ohm ,3 ohm, 4 ohm and 5 ohm are connected in series and after ward in parallel calculate the resistance in each case

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User Obysky
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2 Answers

6 votes

Answer:

in series = 14 ohms, in parallel =
(60)/(77)

Step-by-step explanation:

answered
User Mapsy
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8.3k points
4 votes
When resistors are connected in series, their resistances add up. Therefore, when the resistors of 2 ohm, 3 ohm, 4 ohm, and 5 ohm are connected in series, the total resistance can be calculated by summing them:

Total resistance in series = 2 ohm + 3 ohm + 4 ohm + 5 ohm = 14 ohm.

When resistors are connected in parallel, the reciprocal of their resistances adds up. Thus, the total resistance in parallel can be calculated as follows:

Total resistance in parallel = 1 / (1/2 ohm + 1/3 ohm + 1/4 ohm + 1/5 ohm).

To simplify the calculation, we can find a common denominator for the reciprocals:

Total resistance in parallel = 1 / (30/60 + 20/60 + 15/60 + 12/60) ohm
= 1 / (77/60) ohm
= 60 / 77 ohm (approximately 0.7792 ohm).

Therefore, when the resistors of 2 ohm, 3 ohm, 4 ohm, and 5 ohm are connected in parallel, the total resistance is approximately 0.7792 ohm.
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User Sorceror
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