Question

Amy plants to buy watermelon in a supermarket she found that the average weight of the watermelon is 20 pounds with a standard deviation of 5 pounds what is the mean and standard deviation of the sampling distribution of the sample mean a sample of 5 watermelon

Answer 1

The mean (μ) of the sampling distribution of the sample mean is equal to the population mean, which is 20 pounds.

Explanation:

The standard deviation (σ) of the sampling distribution of the sample mean is equal to the population standard deviation divided by the square root of the sample size:

σ = 5 / sqrt(5) ≈ 2.24 pounds (rounded to two decimal places)

Therefore, the mean of the sampling distribution of the sample mean is 20 pounds and the standard deviation is approximately 2.24 pounds when samples of size 5 are taken from the population of watermelons with a mean of 20 pounds and a standard deviation of 5 pounds.