Question

Need help fast!!
Solve for x

Answer 1

`D:2x^2+1\geq0\\D:2x^2\geq-1\\D:x^2\geq-(1)/(2)\\D:x\in\mathbb{R}\\\\√(2x^2+1)=2\\2x^2+1=4\\2x^2=3\\x^2=(3)/(2)\\x=-\sqrt{(3)/(2)} \vee x=\sqrt{(3)/(2)}\\x=-(\sqrt6)/(2) \vee x=(\sqrt6)/(2)`