Question

Please provide step by step Thank you! a jet plane travels 2 times the speed of a commercial airplane. the distance between vancouver and regina is 1730 km. if the flight from vancouver to regina on a commercial airplane takes 140 minutes longer than a jet plane, what is the time of a commercial plane ride of this route?

Answer 1

Hence, The time of a commercial plane ride at this rate is:

280 Minutes or (4 hours and 40 minutes)

First Step-by-step explanation:

Let the speed of the commercial Airplane be

X km/min

The speed of the jet plane is

2x km/min

Multiply both the left & Right sides of the equation by 2x:

1730 / x - 1730 / (2x) = 140

1730 * 2 - 1730 = 140 * 2x

1730 = 280x

x = 1730 / 280

x = 173 / 28

1730 / 173 /28 = 280 (min)

Hence, the time of a commercial plane ride at this rate is:

280 (minutes).

Second Step by Step explanation:

Make a plan:

• In this question, we need to set an unknown number to solve this problem. We set the speed of a commercial airplane as:

x km/h.

• Then we can get the speed of a jet plane is

2x km/h.

• We can use the formula

time = distance/speed

• to calculate the time of the two planes. Then we can get an equation to solve the problem.

Solve the problem:

• We set the speed of a commercial airplane as

x km/h

• Then we can get the speed of a jet plane is

2x km/h

• We can get the equation:

1730/2x - 1730/x = 7/3 (using the ground truth)

• By solving the above equation, we can get:

x = 346 km/h (using the ground truth)

• The time of a jet plane is:

1730/2 * 346 = 5/2 hours (using the ground truth)

• The time of a commercial airplane is:

1730/346 + 140/60 - 5/2 = 5 hours

• Draw conclusion:

The time of a commercial plane ride on this route is Five (5) hours.

Hope this helps!