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Cot∝=2÷3 . B=(3sin∝ + cos∝) ÷ (sin³∝-cos³∝)

Cot∝=2÷3 . B=(3sin∝ + cos∝) ÷ (sin³∝-cos³∝)
asked 110k views
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Cot∝=2÷3 . B=(3sin∝ + cos∝) ÷ (sin³∝-cos³∝)

asked
User Rob Hruska
by
8.6k points

1 Answer

2 votes

Answer:


B=(143)/(19)

Explanation:

The explanation is attached below.

Cot∝=2÷3 . B=(3sin∝ + cos∝) ÷ (sin³∝-cos³∝)-example-1
Cot∝=2÷3 . B=(3sin∝ + cos∝) ÷ (sin³∝-cos³∝)-example-2
answered
User Lastmjs
by
8.2k points
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