Question

Distribute: -3x(2x^2 – x + 11)

A. 6x^2 - 4x + 11

B. -6x^2 + 3x^2 - 33x

C. 6x^3 - 3x^2 - 33x

D. -6x^3 + 3x^2 – 33x​

Answer 1

I think the answer is D. -6x^3 + 3x^2 - 33x

-3x(2x^ 2 - x + 11)
-3x distributed into 2x is -6x^3. When the bases are the same when you are multiplying you add the exponents together.
-3x distributed into -x is positive 3x^2.
-3x distributed into 11 is -33x.
Together the answer should be -6x^ 3 + 3x^2 -33x