Question

QUESTION 6
Solve for a. (round to tenths)
8
a
14

Answer 1

To solve this, use the Pythagorean theorem (a^2+b^2=c^2) as it is a right triangle.

Seeing that c^2 is occupied with a value, we would want to subtract c^2 (14) by b^2 (8) to figure out a^2.

Thusly, we come up with c^2 (14)^2 - b^2 (8)^2 = a^2

Once simplified, we get 196-64 = a^2, which is 132 = a^2.

Now, simplify once again by square rooting both sides of the equation.
By doing so, we get:

A = 11.5 (rounded to tenths).

Answer 2

11.5

Explanation:

Given:

Left side = 8

Bottom = a

Right side = 14

Using the Pythagorean theorem:

`ax^(2)` +
`8x^(2)` =
`14x^(2)`

Simplifying the equation:

`ax^(2)` + 64 = 196

Subtracting 64 from both sides:

`ax^(2)` = 132

Taking the square root of both sides:

a =
`√(132)`

Calculating the approximate value of "a":

a ≈ 11.5 (rounded to the nearest tenth)

Therefore, the value of "a" in the given right triangle is approximately 11.5.