Question

As an Acapulco cliff diver drops to the water from a height of 46m, his gravitational potential energy decreases by 25,000 J. What is the diver's weight in Newtons?

The textbook says the answer is 0.54 kN

I used the formula: U=mgh and get 55.54

m=?

h=46 m

U=25,000J

g= 9.8 m/s^2

Why isn't g being plugged in the textbook answer?

Answer 1

Answer: 543.48N / 0.54kN

Reason:
change in gpe = 25000N = mgh

Since weight = mg,
Then weight = 25000N/h
which is 25000N/46m

Therefore, weight = 543.48N / 0.54kN