asked 117k views
5 votes
Determine the values r for which the given differential equation has the solution of the form y = e^(rt) . y" + 13y -30y = 0

asked
User Francs
by
8.5k points

1 Answer

1 vote

Final answer:

To determine the values of r for which the given differential equation has the solution of the form y = e^(rt), we substitute the solution into the equation and solve for r. The values of r that satisfy the equation are 2 and -15.

Step-by-step explanation:

To determine the values of r for which the given differential equation has the solution of the form y = e^(rt), we need to substitute this solution into the differential equation and find the values of r that satisfy the equation. The given differential equation is y" + 13y - 30y = 0. Substituting y = e^(rt) into the equation:

e^(rt)" + 13e^(rt) - 30e^(rt) = 0

Using the fact that the second derivative of y = e^(rt) is y" = r^2e^(rt), we can rewrite the equation as:

r^2e^(rt) + 13e^(rt) - 30e^(rt) = 0

Factoring out e^(rt), we have:

e^(rt)(r^2 + 13r - 30) = 0

For the equation to be satisfied, either e^(rt) = 0 or r^2 + 13r - 30 = 0. Since e^(rt) is never equal to zero, we only need to solve the quadratic equation:

r^2 + 13r - 30 = 0

To solve the quadratic equation, we can factor it as (r - 2)(r + 15) = 0. Therefore, the values of r that satisfy the given differential equation are r = 2 and r = -15.

answered
User Omar Abdan
by
8.1k points

Related questions

1 answer
0 votes
159k views
asked Jun 9, 2021 93.9k views
Artem Svirskyi asked Jun 9, 2021
by Artem Svirskyi
8.6k points
1 answer
1 vote
93.9k views
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.