Question

Find the slope of the line passing through the points (-2, 3) and (-8, 8). Fill in the blanks below. Find the slope of the line passing through the points (-7, 6) and (3,6). slope: ___

Find the slope of the line passing through the points (-2,9) and (-2,5). slope: ___

Answer 1

`\begin{gathered}\longrightarrow\sf{m=-(5)/(6)\\\longrightarrow\sf{m=0}\\\longrightarrow\sf{m=not\:de fined}}\end{gathered}`

In-depth explanation:

Hi there, let's find the slope.

Main Idea: To find the slope, use the formula:

`\sf{m=(y_2-y_1)/(x_2-x_1)}`

Where:

• m = slope

`\rule{350}{1}`

Question 1

Find the slope of the line passing through the points (-2, 3) and (-8, 8)

Plug the data into the formula:

`\sf{m=(y_2-y_1)/(x_2-x_1)}`

`\sf{m=(8-3)/(-8-(-2))}`

`\sf{m=(5)/(-8+2)}`

`\sf{m=(5)/(-6)}`

`\boxed{\bf{m=-(5)/(6)}}`

Therefore, the slope of the line that passes through the points (-2,3) and (-8,8) is -5/6.

`\rule{350}{1}`

Question 2

Find the slope of the line passing through the points (-7, 6) and (3,6)

Plug the data into the formula:

`\sf{m=(6-6)/(3-(-7))}`

`\sf{m=(0)/(3+7)}`

`\sf{m=(0)/(10)}`

`\boxed{\bf{m=0}}`

Therefore, the slope of the line passing through the points (-7,6) and (-3,6) is 0.

`\rule{350}{1}`

Question 3

Find the slope of the line passing through the points (-2,9) and (-2,5).

Plug the data into the formula:

`\sf{m=(5-9)/(-2(-2))}`

`\sf{m=(5-9)/(-2+2)}`

`\sf{m=(-4)/(0)}`

`\boxed{\bf{m=not\:de fined}}`

Therefore, the slope of the line that passes through (-2,9) and (-2,5) is not defined.