Question

Take a factor out of the square root:

√48x^2, where x≤0

Answer 1

Answer:
`-4\text{x}√(3)`

Work Shown:

`\sqrt{48\text{x}^2}=\sqrt{3*16\text{x}^2}\\\\=√(3)*\sqrt{16\text{x}^2}\\\\=√(3)*\sqrt{4^2*\text{x}^2}\\\\=√(3)*√(4^2)*\sqrt{\text{x}^2}\\\\=√(3)*4(-\text{x}) \ \ \text{... see note below}\\\\=-4\text{x}√(3)\\\\`

Note:
`\text{If x} \le 0, \text{ then } \sqrt{\text{x}^2} = -\text{x}`