Question

6) Lily was going to have a party so she

bought some sweets.She bought some
cookies and brownies. Cookies were $2 and
brownies were $3. She spent $144 for a total
of 60 sweets. How many cookies and
brownies did she buy?

Answer 1

Let's assume the number of cookies Lily bought is represented by "C," and the number of brownies is represented by "B."

According to the problem, the cost of one cookie is $2, and the cost of one brownie is $3. Lily spent a total of $144.

We can set up two equations based on the given information:

C + B = 60 (equation 1, representing the total number of sweets)

2C + 3B = 144 (equation 2, representing the total cost in dollars)

To solve this system of equations, we can use substitution or elimination method. Here, we'll use the substitution method.

From equation 1, we can rewrite it as C = 60 - B.

Now substitute this value of C in equation 2:

2(60 - B) + 3B = 144

Simplify the equation:

120 - 2B + 3B = 144

Combine like terms:

120 + B = 144

Subtract 120 from both sides:

B = 144 - 120

B = 24

Now substitute the value of B back into equation 1 to find C:

C + 24 = 60

C = 60 - 24

C = 36

Therefore, Lily bought 36 cookies and 24 brownies.