Answer:
We can use the formula for the nth term of an arithmetic sequence to find n:
an = a1 + (n - 1)d
Substituting the given values, we get:
52 = 132 + (n - 1)(-4)
Simplifying and solving for n, we get:
n = 21
So, the sequence has 21 terms.
We can use the formula for the sum of the first n terms of an arithmetic sequence to find Sn:
Sn = n/2(2a1 + (n - 1)d)
Substituting the given values, we get:
Sn = 21/2(2(132) + (21 - 1)(-4))
Simplifying, we get:
Sn = 21/2(264 - 80)
Sn = 21/2(184)
Sn = 1932
Therefore, the sum of the first 21 terms of the arithmetic sequence is 1932.