Question

A gas is initially at 20.0 o C. That temperature is

K.

The gas is then heated to 30.0 0 C. That temperature is
K.


The initial pressure of the gas is 1.00 atm. The new pressure of the gas is
atm. (Round to 2 decimal places)

Answer 1

The temperature of the gas is 293.15 K.

The temperature of the gas is 303.15 K.

The new pressure of the gas is 0.97 atm.

Step-by-step explanation:

You need to add 273.15 to the Celsius temperature to convert from Celsius to Kelvin.

So,

20.0°C + 273.15 = 293.15 K.

30.0°C + 273.15 = 303.15 K.

We can use the following equation to calculate the new pressure:

`P_2 = P_1 *(T_2)/(T_1)`

where:

• P1 is the initial pressure
• P2 is the final pressure
• T1 is the initial temperature

• T2 is the final temperature

Plugging in the values from the problem, we get:

`P_2 = 1.00 atm * (303.15 K )/(293.15 K) = 0.97 atm`

Therefore, the new pressure of the gas is 0.97 atm.