Question

What is the pressure in atm of a 5.00 l tank with 5.95 moles of oxygen at 39.3 degrees Celsius

Answer 1

We can use the ideal gas law to solve for the pressure:

PV = nRT

where P is the pressure in atm, V is the volume in liters, n is the number of moles, R is the gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin (K).

First, we need to convert the temperature from Celsius to Kelvin:

T = 39.3 + 273.15

T = 312.45 K

Now we can plug in the values we have:

P(5.00 L) = (5.95 mol)(0.0821 L·atm/mol·K)(312.45 K)

P = (5.95)(0.0821)(312.45) / 5.00

P = 2.98 atm

Therefore, the pressure in the tank is 2.98 atm.