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If one sttarts with 80000 counts, how many counts would be expected after 4 half lives

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6 votes

Answer:

The term referring to is radioactive decay.

To answer the question, we need to know the half-life of the radioactive material. Let's assume the half-life is 10,000 counts.

After one half-life, the count would be halved to 40,000 counts. After the second half-life, the count would be halved again to 20,000 counts. After the third half-life, the count would be halved again to 10,000 counts. And after the fourth half-life, the count would be halved again to 5,000 counts.

So after 4 half-lives, we would expect the count to be 5,000.

After 4 half-lives, the remaining number of counts would be calculated by dividing the initial number of counts by 2 raised to the power of the number of half-lives. In this case:

Initial counts: 80,000

Number of half-lives: 4

Remaining counts = 80,000 / (2^4) = 80,000 / 16 = 5,000 countsSo, after 4 half-lives, you would expect to have 5,000 counts remaining.

Step-by-step explanation:

answered
User Sisu
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7.9k points
5 votes

Answer:

The term referring to is radioactive decay.

To answer the question, we need to know the half-life of the radioactive material. Let's assume the half-life is 10,000 counts.

After one half-life, the count would be halved to 40,000 counts. After the second half-life, the count would be halved again to 20,000 counts. After the third half-life, the count would be halved again to 10,000 counts. And after the fourth half-life, the count would be halved again to 5,000 counts.

So after 4 half-lives, we would expect the count to be 5,000.

After 4 half-lives, the remaining number of counts would be calculated by dividing the initial number of counts by 2 raised to the power of the number of half-lives. In this case:

Initial counts: 80,000

Number of half-lives: 4

Remaining counts = 80,000 / (2^4) = 80,000 / 16 = 5,000 countsSo, after 4 half-lives, you would expect to have 5,000 counts remaining.

answered
User Sumod Badchhape
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7.7k points