Question

two slits, each of width 1.8um and separated by the center-to-center distance of 5.4um, are illuminated by plane waves from a krypton ion laser with a wavelength of 461.9 nm.

Answer 1

The number of interference peaks in the central diffraction peak of a double-slit setup can be calculated using the formula n = (2d/λ) + 1.

Step-by-step explanation:

The phenomenon described in the question is called double-slit interference. When light passes through two slits that are separated by a certain distance, it creates an interference pattern consisting of bright and dark fringes. The number of interference peaks in the central diffraction peak can be determined using the formula:

n = (2d/λ) + 1

Where n is the number of interference peaks, d is the distance between the slits, and λ is the wavelength of the light. Plugging in the given values, we get:

n = (2 * 5.4 × 10-4 m) / (461.9 × 10-9 m) + 1 = 2331.

Answer 2

This college-level physics question asks for the determination of the number of interference peaks within the central diffraction peak created by light from a krypton ion laser as it passes through two slits.

Step-by-step explanation:

The student's question involves the physics of interference and diffraction patterns created when light passes through multiple slits. This phenomenon is described by the principles of wave optics. In particular, the question asks to identify the number of interference peaks within the central diffraction peak when a krypton ion laser with a wavelength of 461.9 nm illuminates two slits that have a specified width and separation.

The calculation for the interference pattern involves the use of the formula d*sin(θ) = m*λ, where d is the slit separation, λ is the wavelength of the incident light, m is the order of the interference maximum, and θ is the angle of interference. To find the number of interference peaks within the main diffraction peak, additional considerations of slit width and slit separation need to be applied.