Final answer:
The maximum vertical distance between the line y = x + 42 and the parabola y = x² for -6 ≤ x ≤ 7 is 42.
Step-by-step explanation:
To find the maximum vertical distance between the line y = x + 42 and the parabola y = x² for -6 ≤ x ≤ 7, we need to find the highest point on the parabola that is above or below the line. We can do this by finding the vertex of the parabola and comparing its y-coordinate with the y-coordinate of the line at that x-value.
The vertex of the parabola y = x² is the point (h, k), where h is given by the formula h = -b/(2a) and k is the y-coordinate of the vertex. In this case, a = 1 and b = 0, so h = 0 and k = 0. This means that the vertex of the parabola is at the point (0, 0).
Substituting x = 0 into the equation of the line y = x + 42, we get y = 0 + 42 = 42. Therefore, the maximum vertical distance between the line y = x + 42 and the parabola y = x² is 42.