Question

a 4.8-g bullet leaves the muzzle of a rifle with a speed of 334 m/s. what force (assumed constant) is exerted on the bullet while it is traveling down the 0.79-m-long barrel of the rifle?

Answer 1

Step-by-step explanation:

From 0 to 334 m/s is average velocity of 167 m/s

so to travel the barrel length takes = .79 m / 167 m/s = .0047305 s

the is leads to acceleration of 334 m/ / .0047305 m/s = 70,605 m/s^2

F = ma

= .004 kg * 70 605 m/s^2 = 282 N