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Find the surface area of the regular pyramid.

A square pyramid. The length of the base is 1 inch. The height of each triangular face is 2 inches.

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Answer:

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Explanation:

A square pyramid has 5 faces: 1 square base and 4 triangular faces. The surface area of the pyramid is the sum of the areas of all its faces.

The area of the square base is 1 * 1 = 1 square inch.

The area of each triangular face is (1/2) * base * height = (1/2) * 1 * 2 = 1 square inch.

Since there are 4 triangular faces, the total area of the triangular faces is 4 * 1 = 4 square inches.

Therefore, the surface area of the pyramid is 1 + 4 = 5 square inches.

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