Answer:
a False
b False
c. True
Explanation:
a) False, because if for example p = 3, then 22p - 1 = 66 - 1 = 65 which is not prime.
b) Lets look at an example
ab = ac mod n
Let a = 3, b = 4 and c = 9:
12 = 27 mod 15 ( as 12 is the remainder when 27 is divided by 15)
Divide ab and ac by a ( = 3) we have
4 = 9 mod 15
bt 9 mod 15 is 9
so FALSE.
c)
a|c and b|c means a divides exactly into c and b divides exactly into c.
So we can write ak = c and bl = c where k and l are 2 integers ( not = 0).
Therefore ak = bl
so a^2b^2kl = c^2 which is divisible by ab.
True