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Log(100x2y5) = log(100) + log(2) + log(y) + log(5)
= 2 + log(2) + log(y) + log(5)
= 2 + 1 + log(y) + log(5)
= 3 + log(y) + log(5)
= 3 + log(y5)
= 3 + log(250)
= 3 + 2.39794
= 5.39794
Answer:
Sure! Using the properties of logarithms, we can expand log(100x^2y^5) as follows:
log(100x^2y^5) = log(100) + log(x^2) + log(y^5)
= log(10^2) + 2*log(x) + 5*log(y)
= 2 + 2*log(x) + 5*log(y).