Answer:
a. Punnett square for the cross of a snake that is homozygous dominant for the red color (RR) with a snake that is heterozygous for the red color (Rr):
```
| R | R |
----------------
| RR | RR | RR |
----------------
| Rr | Rr | Rr |
```
In this cross, all the offspring (100%) will have the red pigment in their skin because the presence of red pigment (R) is dominant over its absence (r).
b. Punnett square for the cross of two snakes that are heterozygous for the black color (Bb):
```
| B | b |
----------------
| BB | BB | Bb |
----------------
| Bb | Bb | bb |
```
In this cross, 75% of the offspring are expected to have black pigment in their skin (BB and Bb genotypes), and 25% of the offspring are expected to lack black pigment (bb genotype) due to the absence of the dominant black allele (B).
c. Both parent snakes are homozygous recessive for the red gene (rr), meaning they lack the red pigment. Since the red gene and black gene are independent of each other, the absence of red pigment does not affect the inheritance of the black pigment. Therefore, the percentage of offspring expected to lack both red and black pigments in their skin would be the same as the percentage of offspring lacking the black pigment (bb genotype) in the Punnett square from part (b). Thus, 25% of their offspring are expected to lack both the red and black pigments in their skin.