Question

What are the exact solutions of x2 − 3x − 1 = 0 using x equals negative b plus or minus the square root of the quantity b squared minus 4 times a times c all over 2 times a? a x = the quantity of 3 plus or minus the square root of 5 all over 2 b x = the quantity of negative 3 plus or minus the square root of 5 all over 2 c x = the quantity of 3 plus or minus the square root of 13 all over 2 d x = the quantity of negative 3 plus or minus the square root of 13 all over 2

Answer 1

c. x = the quantity of 3 plus or minus the square root of 13 all over 2

Explanation:

Using quadratic formula with a = 1, b = -3, and c = -1.

x = [-(-3) ± √{(-3)^2 - 4(1)(-1)}] / ]2(1)]

x = (3 ± √13)/2

Answer 2

So the correct option is:

d) x = (3 ± √13) / 2

Explanation:

To find the solutions of the equation x^2 - 3x - 1 = 0 using the quadratic formula, which is x = (-b ± √(b^2 - 4ac)) / (2a), we can identify the values of a, b, and c from the given equation.

a = 1

b = -3

c = -1

Substituting these values into the quadratic formula, we get:

x = (-(-3) ± √((-3)^2 - 4(1)(-1))) / (2(1))

Simplifying further:

x = (3 ± √(9 + 4)) / 2

x = (3 ± √13) / 2

Therefore, the exact solutions of the equation x^2 - 3x - 1 = 0 are:

x = (3 + √13) / 2

x = (3 - √13) / 2