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15.00 ml of 1.00 m hcl diluted to 0.500 l calculate the ph

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Answer: 1.52

To calculate the pH, we need to first find the new concentration of the HCl solution after dilution:

moles of HCl in initial solution = 15.00 ml x 1.00 mol/L = 0.015 mol
new concentration of HCl = moles/volume = 0.015 mol/0.500 L = 0.030 mol/L

Next, we can use the definition of pH:

pH = -log[H+]

where [H+] is the concentration of hydrogen ions in solution. In this case, since HCl is a strong acid, it completely dissociates into H+ and Cl- ions in solution. Therefore, the concentration of H+ is equal to the concentration of HCl:

[H+] = 0.030 mol/L

Finally, we can plug this into the pH equation:

pH = -log(0.030) = 1.52

Therefore, the pH of the diluted HCl solution is 1.52.
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