Question

Consider the following diagrams, where F represents the focal point of a concave lens. In these diagrams, the image formed by the lens is obtained using the ray tracing technique. Which diagrams are accurate?(Figure 1)

A)Type A if you think that only diagram A is correct, type AB if you think that only diagrams A and B are correct, and so on.
B)If the focal length of the concave lens is -7.50cm , at what distance do from the lens should an object be placed so that its image is formed 3.70cm from the lens?
Express your answer in centimeters.
do= cm
C)What is the magnification m produced by the concave lens described in Part B?
Express your answer numerically.
m=

Answer 1

The accurate diagrams for the image formation by a concave lens are A and B. The object distance needed to form an image 3.70cm from the lens can be calculated using the thin lens equation. The magnification produced by the concave lens can be determined using the formula -di/do.

Step-by-step explanation:

The diagrams that accurately represent the image formation by a concave lens are diagram A and B. In diagram A, the image is formed on the same side of the lens as the object, and it is smaller in size. In diagram B, the image is formed on the same side of the lens as the object, and it is also smaller in size.

To determine the distance at which an object should be placed from a concave lens to form an image 3.70cm from the lens, you can use the thin lens equation: 1/f = 1/do + 1/di, where f is the focal length (given as -7.50cm), do is the object distance (unknown), and di is the image distance (-3.70cm). By substituting the given values, you can solve for do.

The magnification (m) produced by the concave lens is given by the formula: m = -di/do. By substituting the known values of di and do, you can calculate the magnification.

Answer 2

A The ray diagrams in A and C are accurate

b. Focal length is -7.3 cm

cThe magnification is 0.50 meters

How to get the solution

The ray diagrams A and C are correct given that the image formed is virtual and erect.

1/v - 1/u = 1/f

1/-3.7 - 1/u = 1/-7.5

1/u = -0.1369369369

1 = -0.1369369369u

u = 1 / -0.1369369369

= -7.3026

magnification = -3.7 / -7.3026

= 0.50