asked 56.6k views
2 votes
What is an equation of the line that passes through the point (- 2, - 4) and is parallel to the line 5x - 2u = 6 ?

asked
User Konzo
by
8.9k points

1 Answer

6 votes
Answer: 5x - 2y = -2

To find the equation of the line, we need to determine its slope. Since the line we want to find is parallel to the given line, it has the same slope as the given line.

To find the slope of the given line, we can rearrange it into slope-intercept form:

5x - 2y = 6

-2y = -5x + 6

y = (5/2)x - 3

So the slope of the given line is 5/2.

Now we can use the point-slope form of a line to write the equation of the line we want to find:

y - y1 = m(x - x1)

where m is the slope and (x1, y1) is the point (-2, -4) we want the line to pass through.

Substituting m = 5/2, x1 = -2, and y1 = -4, we get:

y - (-4) = (5/2)(x - (-2))

y + 4 = (5/2)(x + 2)

Multiplying both sides by 2 to eliminate the fraction, we get:

2y + 8 = 5x + 10

Subtracting 5x and 8 from both sides, we obtain the final form of the equation:

5x - 2y = -2
answered
User Oleg Popov
by
7.8k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.