Question

In the figure below, the current in the long, straight wire is I1 = 3.90 A, and the wire lies in the plane of the rectangular loop, which carries 13.6 A. The dimensions shown are c = 0.100 m, a = 0.150 m, and l = 0.450 m. Find the magnitude and direction of the net force exerted by the magnetic field due to the straight wire on the loop.

Answer 1

The net force exerted by the magnetic field due to the straight wire on the loop is zero.

Step-by-step explanation:

To find the net force exerted by the magnetic field due to the straight wire on the loop, we can use the equation F = I * l * B * sin(theta), where F is the force, I is the current, l is the length of the wire, B is the magnetic field, and theta is the angle between the wire and the magnetic field.

Since the wire and the loop are parallel, the angle between them is 0 degrees, so sin(theta) = 0. Therefore, the force would be zero.