Register

F(x)=(x-1)(x-2)(x-3)(x-4)(x-3)(x-2)(x-2)/[(x-2)(x-4)(x-2)]

F(x)=(x-1)(x-2)(x-3)(x-4)(x-3)(x-2)(x-2)/[(x-2)(x-4)(x-2)]
asked 68.5k views
3 votes
F(x)=(x-1)(x-2)(x-3)(x-4)(x-3)(x-2)(x-2)/[(x-2)(x-4)(x-2)]

asked
User Rafareino
by
8.0k points

1 Answer

4 votes

Answer:

Explanation:

(x-2)(x-2)(x-4)

answered
User JustAndrei
by
8.9k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!