Answer:
Explanation:
First , Ab and CD are 2 parallel lines, but to be so, they need to have the same constant of their equation. Lets find the equation of AB first.
A(-4;-6)^B(0;-2) and we use the formula (y-yA)/(yB-yA)=(x-xA)/(xB-xA)
Just replace the data we have and it will be y=2x+2
Constant is equal to 2, so either CD will have the same constant=2. When we know ony one poin we use this formula:
y-yC=k*(x-xC) Replace the coordinates of C and it will be y=2x+8. This is the equation of CD. To find the y that the exercise wants, we will replace the coordinates of D(0;y) in y=2x+8
=> y=8 . So the value of y is equal to 8