Question

Here is the start of a sequence. Lucas extends this sequence and finds that the

21st term in the sequence is 65. What is the 22nd term?
125 122 119 116 113

Answer 1

Answer: 62

Explanation:

A.P = 125, 122, 119, 116, 113

here,

a (first term) = 125

d (common difference) = 122-125 = -3

nth term = a + (n-1)d

we need to find the 22nd term so

22nd term = 125 + (22-1) x (-3)

= 125 - (21 x -3)

= 125 - 63 = 62