Question

if you dissolve 93.1g of k2CO3(s) (molar mass=136.21 g/mol) in enough water to produce a solution with a volume of 1.09 L. what is the molarity

Answer 1

Answer: The molarity of the K2CO3 solution is 0.625 M.

Explanation: To find the molarity of a solution, you need to know the moles of solute and the volume of the solution in liters. Here's how to solve the problem:

Calculate the moles of K2CO3 using its given mass and molar mass:

moles = mass / molar mass = 93.1 g / 136.21 g/mol = 0.682 mol

Calculate the volume of the solution in liters:

volume = 1.09 L

Calculate the molarity of the solution using the moles and volume:

molarity = moles / volume = 0.682 mol / 1.09 L = 0.625 M