Question

After an electric sign is turned on, the temperature of its glass goes from 23.5°C to 65.5°C. The sign’s glass has a mass of 905 grams, and the specific heat capacity of the glass is 0.67 J/g

°C. How much heat did the glass absorb?

In the first box type in the number you calculated, in the second box type your unit.

Answer 1

To calculate the amount of heat absorbed by the glass, we can use the formula:

Q = mcΔT

where Q is the heat absorbed, m is the mass of the glass, c is the specific heat capacity, and ΔT is the change in temperature.

Given:
m = 905 grams
c = 0.67 J/g°C
ΔT = (65.5°C - 23.5°C) = 42°C

Substituting the values into the formula:

Q = (905 grams) * (0.67 J/g°C) * (42°C)

Calculating the product:

Q = 26066.35 J

Therefore, the glass absorbed approximately 26066.35 Joules of heat.

In the first box, the calculated number is 26066.35. In the second box, the unit is Joules (J).