Question

a copper wire is 1.7 mm in diameter and carries a current of 20 a . part a what is the electric field strength inside this wire? express your answer with the appropriate units.

Answer 1

The electric field strength inside the copper wire is approximately 100.925 kV/m.

Step-by-step explanation:

The electric field strength inside the wire can be determined using Ohm's law and the relationship between current and electric field.

First, calculate the radius of the wire by dividing the diameter by 2: 1.7 mm / 2 = 0.85 mm.

Next, convert the radius to meters: 0.85 mm = 0.85 x 10-3 m.

Then, use the formula E = (I / σr)J, where E is the electric field strength, I is the current, σ is the resistivity of copper (1.68 x 10-8 Ωm), and r is the radius of the wire.

Substituting the values, we get E = (20 A / (1.68 x 10-8 Ωm x (0.85 x 10-3 m)2) = 100925 E-3 V/m = 100.925 kV/m.

Therefore, the electric field strength inside the wire is approximately 100.925 kV/m.