Question

Calculate the volume in L of Oxygen gas collected at STP if the sample has a mass of 2.67g?

Answer 1

`\huge\boxed{\sf 1.869\ L}`

Step-by-step explanation:

Given that,

Mass = m = 2.67 g

Molar mass (O₂) = 16 × 2 = 32 g/mol

Finding no. of moles:

We know that,

• No. of moles = mass in g / molar mass

No. of moles = 2.67 / 32

No. of moles = 0.08 moles

Also, we know that:

1 moles of O₂ at STP = 22.4 L

• Multiply both sides by 0.08

1 × 0.08 moles of O₂ at STP = 22.4 × 0.08 L

0.08 moles of O₂ at STP = 1.869 L

So, the volume of 0.08 moles of oxygen gas at STP will be 1.869 L.

`\rule[225]{225}{2}`