Question

DUE TODAY!! LINEAR FUNCTIONS

What is an equation for the linear function whose graph contains the points (−1,−2) and a slope of 3?

Enter your answers in the boxes.

y+ ? = ? (x+1)

Answer 1

Answer:
Y + 2 = 3( X + 1 )


Step-by-step explanation:
The equation is
Y - Y1 = M(X - X1)

Y1 is the y value:
The y value for the point (-1,-2) is -2 so we can plug that in

Y - (-2) = M( X - X1 )
If you subtract a negative you are adding so:
Y + 2 = M( X - X1 )

X1 stands for X
The X value for (-1,-2) is -1 same as the last one it will be positive because if you subtract a negative you are adding it:
Y + 2 = M( X + 1 )

Finally we plug in M
M is the slope and slope = 3 so plug 3 in
Y + 2 = 3( X + 1 )

Answer is Y + 2 = 3( X + 1 )

Answer 2

The point-slope form of the equation of a line is given by y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope of the line. In this case, we have a point (-1,-2) and a slope of 3. Substituting these values into the equation, we get:

y - (-2) = 3(x - (-1))

Simplifying this equation, we get:

y + 2 = 3(x + 1)

So, the equation for the linear function whose graph contains the point (-1,-2) and has a slope of 3 is y + 2 = 3(x + 1).