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Someone please help!!!!!

Find the probability that a randomly selected point within the circle falls into the red-shaded triangle.

Someone please help!!!!! Find the probability that a randomly selected point within-example-1
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User QIvan
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2 Answers

3 votes

Answer:

To find the probability of a randomly selected point falling into the red-shaded triangle within the circle, compare the area of the triangle to the total area of the circle.

Explanation:

answered
User Williamstome
by
7.6k points
4 votes

The probability that a randomly selected point within the circle falls into the red-shaded triangle is 0.318.

How the probability needed point was determined.

The probability that a randomly selected point within the circle falls into the red-shaded triangle is given by

P(red-shaded triangle) = Area shaded ∆/Area of circle

Area of red-ashaded ∆ = 1/2 * base * height

base = 24

height = 12

A of ∆ = 1/2* 24 * 12

= 288/2

= 144

Area of circle = πr²

r is radius

r = 12

A = π* 12²

= 144π

= 452.448

Probability of chosen point to fall on red-ashaded triangle = 144/452.448

P(red ∆) = 0.318

Therefore,the probability that a randomly selected point within the circle falls into the red-shaded triangle is 0.318.

answered
User CodingMytra
by
7.5k points

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