Answer:
The area of the trapezoid is 3(8 + √3) square units, which is about 29.196 square units.
Explanation:
In each 30°-60°-90° triangle, h = 3 since the length of the shorter side is one-half the length of the hypotenuse. So the length of the longer side of each of these triangles is 3√3 since the length of the longer side is √3 times the length of the shorter side.
Now we compute the area of the trapezoid:
A = (1/2)(3)(8 + √3 + 8 + √3)
= (1/2)(3)(16 + 2√3)
= 3(8 + √3) = about 29.196