Question

the pressure of a 98.11 g sample of arsenic pentafluoride in a 5340 mL container is measured to be 1.36 atm. What is the temperature of this gas in kelvin?

Answer 1

We can use the Ideal Gas Law to solve this problem:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to find the number of moles of arsenic pentafluoride:

n = mass / molar mass

The molar mass of arsenic pentafluoride (AsF5) is:

(1 x atomic mass of As) + (5 x atomic mass of F) = (1 x 74.92 g/mol) + (5 x 18.99 g/mol) = 218.87 g/mol

So, the number of moles is:

n = 98.11 g / 218.87 g/mol = 0.447 mol

Now, we can rearrange the Ideal Gas Law to solve for temperature:

T = PV / nR

We need to make sure that all the units are in the correct SI units, so we convert the volume to liters:

V = 5340 mL = 5.34 L

We also need to use the correct value of the gas constant for the units we are using. We will use R = 0.0821 L·atm/mol·K.

Now we can substitute the values and solve for T:

T = (1.36 atm) x (5.34 L) / (0.447 mol) x (0.0821 L·atm/mol·K) = 369 K

Therefore, the temperature of the gas is 369 K.

Answer 2

To find the temperature of the gas in kelvin, we can use the ideal gas law equation:

PV = nRT

Where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles of the gas
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature (in Kelvin)

First, we need to convert the given values to the appropriate units:
Mass of arsenic pentafluoride = 98.11 g
Volume of the container = 5340 mL = 5.34 L (since 1 L = 1000 mL)
Pressure = 1.36 atm

Next, we need to calculate the number of moles of arsenic pentafluoride:
Molar mass of AsF5 = 98.11 g/mol
Number of moles (n) = mass / molar mass = 98.11 g / 98.11 g/mol = 1 mol

Now we can rearrange the ideal gas law equation to solve for temperature:
T = (PV) / (nR)

Plugging in the values:
T = (1.36 atm * 5.34 L) / (1 mol * 0.0821 L·atm/(mol·K))

Simplifying:
T = 7.2544 atm·L / (0.0821 mol·K)

T = 88.473 K

Therefore, the temperature of the gas is 88.473 Kelvin.