Question

How do your solve this inscribed polygon problem?​

Answer 1

The sum of the opposite angles in a cyclic quadrilateral is
`180^(\circ)`.

Therefore

`6y+23+7x-3=180^(\circ)\\8y-5+7x-5=180^(\circ)\\\\6y+7x=160^(\circ)\\8y+7x=190^(\circ)`

Subtracting the second equation from the first one, we get:

`2y=30^(\circ)\\y=15^(\circ)`

`6\cdot15^(\circ)+7x=160^(\circ)\\90^(\circ)+7x=160^(\circ)\\7x=70^(\circ)\\x=10^(\circ)`