Question

When 25.0 g of ch4 reacts completely with excess chlorine yielding 45.0 g of ch3cl, what is the percentage yield, according to ch4(g) + cl2(g) → ch3cl(g) + hcl(g)?

Answer 1

the answer is 57.03%

Step-by-step explanation:

%yield= ((practical yield)/(theoretical yield))×100%