Question

Factor 6a² - 12a - 5a + 10 by grouping.

O (6a - 5)(a + 2)
(6a - 5)(a - 2)
(6a + 5)(a + 2)
-
O (6a + 5)(a − 2)

Answer 1

Answer: Therefore, the correct factorization by grouping is (a - 2)(6a - 5).

Explanation:

To factor 6a² - 12a - 5a + 10 by grouping, we can group the terms in pairs:

6a² - 12a - 5a + 10

Taking common factors from the first two terms and the last two terms separately:

6a(a - 2) - 5(a - 2)

Now, we can see that (a - 2) is common in both terms, so we can factor it out:

(a - 2)(6a - 5)

Answer 2

Hello!

6a² - 12a - 5a + 10

= 6a² - 17a + 10

= 6a² - 5a - 12a + 10

= (6a² - 5a) + (-12a + 10)

= a(6a - 5) - 2(6a - 5)

= (6a - 5)(a - 2)