Question

A student plays on a see-saw with her father. The student has a weight of 250 N and is seated 2.4 m from the axis of rotation. Her father balances her when he is seated 0.8 m from the axis. The father's weight is

Answer 1

750 N

Explanation:

As the seesaw is balanced, the torque on both ends must be equal.
Weight of the student is 250 N at 2.4 m from the axis
Let the father's weight be x N, at 0.8 m from the axis
= fd
So, 250 * 2.4 = 0.8 * x
Solving for x, the father's weight is 750 N