Question

For the equilibrium system described by

2 SO2 (g) + O2 (g) 2SO3, (g)

The equilibrium concentrations of SO2, O2, and SO3, were 0.75 M, 0.30 M, and 0.15 M, respectively.


Calculate the equilibrium constant, K. * for the reaction.

Answer 1

Answer: The reaction's equilibrium constant (K) will be around 0.1333.

Step-by-step explanation:

In order to do this, first off you need to know the reactant and product equilibrium concentrations in order to determine the equilibrium constant (K) for the given reaction. The equilibrium concentrations are as follows based on the data given:

[SO2] = 0.75 M [O2] = 0.30 M

[SO3] = 0.15 M

For the indicated reaction, the equation for the equilibrium constant is:

K is equal to ([SO3]2 / ([SO2]2 * [O2])

the equilibrium concentrations into the equation:

K = (0.15^2) / (0.75^2 * 0.30)

K = 0.0225 / 0.16875

(Rounded to four decimal places) K = 0.1333

As a result, the reaction's equilibrium constant (K) is around 0.1333.