Answer:
22°C + 14.82°C = 36.82°C
Step-by-step explanation:
We can use the formula:
q = mCΔT
where q is the heat absorbed by the water, m is the mass of the water, C is the specific heat of water, and ΔT is the temperature change of the water.
We are given q = 12,357 J, m = 234.2 g, and an initial temperature of 22C. The specific heat of water is 4.184 J/(g·°C).
Plugging in the numbers, we get:
12,357 J = (234.2 g)(4.184 J/(g·°C))(ΔT)
Solving for ΔT, we get:
ΔT = 14.82°C
Therefore, the final temperature of the water would be:
22°C + 14.82°C = 36.82°C