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A body is dropped from rest at a height of 80m. How long does it take to reach the ground. g=10ms

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User Omnesia
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1 Answer

7 votes

Answer:

Using the kinematic equation:

h = 1/2 * g * t^2

where h is the initial height (80m), g is the acceleration due to gravity (-10 m/s^2), and t is the time it takes to reach the ground, we can solve for t:

t = sqrt(2h/g)

t = sqrt(2(80m)/10m/s^2)

t = 8 seconds

Therefore, it takes 8 seconds for the body to reach the ground.

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User Arya McCarthy
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